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Mathematics 17 Online
OpenStudy (anonymous):

120 = x^ - 12x^2 + 32x In order for it to be standard form do I have to subtract 120 from each side so it becomes f (x) = x^3 -12x^2 + 32x - 120 120 = x^ - 12x^2 + 32x In order for it to be standard form do I have to subtract 120 from each side so it becomes f (x) = x^3 -12x^2 + 32x - 120 @Mathematics

hero (hero):

x^3 -12x^2 + 32x - 120 =0 , not f(x)

OpenStudy (anonymous):

Oh ok thank you :)

OpenStudy (anonymous):

hi i'm caitlin your hot

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