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OpenStudy (anonymous):
find the limit x--> inf. sin(n {lambda}/2) / n find the limit x--> inf. sin(n {lambda}/2) / n @Mathematics
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OpenStudy (zarkon):
limit x or limit n?
OpenStudy (anonymous):
limit n..:)
OpenStudy (zarkon):
0
OpenStudy (anonymous):
well, i would like to know how to do it
OpenStudy (zarkon):
the numerator is bounded between -1 and 1. the denominator is going to infinity. use the squeeze theorem to get 0
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