Question

factoring trinomials in type ax^2+bx+c. factor completely. if it is a prime state it. 6x^3-4x^2-10x

Answer 1

what are the steps in factoring it?

Answer 2

6x^3-4x^2-10x
= 2x(3x^2 - 2x - 5)
= 2x[3x^2 - 5x + 3x -5]
= 2x[x(3x - 5) +1(3x - 5)]
= 2x[(x + 1)(3x - 5)]
= 2x(x + 1)(3x - 5)

Answer 3

First we take out the common factor 2x
For the polynomial in the bracket a=3, b= -2 and c= -5
Then we calculate a*c = 3*(-5) = -15
Next we find two factors of -15, say X and Y, such that X*Y = a*c i.e. -15 and X+Y = b = -2
With a little work we find the combination of -5 and 3
rest is self-explanatory.......

Hope that explains it for you................☺

Answer 4

yes it does i understand it pretty clearly now. I just did not understand the factoring part itself. Thank you very much for helping.