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Mathematics 13 Online
OpenStudy (anonymous):

[3x+1]/16+[2x-3]/7=[x+3]/8+[3x-1]/14 Value for X please

OpenStudy (anonymous):

it's actually 5 someone answered me check your method and steps

jhonyy9 (jhonyy9):

check the common denominator for 16,7,8 and 14 firstly

OpenStudy (anonymous):

yes it is 5 i was messed up with denominator

OpenStudy (anonymous):

actually solving maths without pen and paper somtimes difficult

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