At the start of 2005, an online social group had 1 million members. Since that time, new members joined at a rate of approximately
m(t) = 12t2 − 20t + 10 million members per year (0 ≤ t ≤ 3.5)
where t is time in years since the start of 2005.

(a) Find an expression for the total online social group membership M(t) at time t.

(b) Use the answer to part (a) to estimate the online social group membership midway through 2008.
M(3.5) = million members At the start of 2005, an online social group had 1 million members. Since that time, new members joined at a rate of approximately
m(t) = 12t2 − 20t + 10 million members per year (0 ≤ t ≤ 3.5)
where t is time in years since the start of 2005.

(a) Find an expression for the total online social group membership M(t) at time t.

(b) Use the answer to part (a) to estimate the online social group membership midway through 2008.
M(3.5) = million members @Mathematics

Question

At the start of 2005, an online social group had 1 million members. Since that time, new members joined at a rate of approximately
m(t) = 12t2 − 20t + 10 million members per year    (0 ≤ t ≤ 3.5)
where t is time in years since the start of 2005.

(a) Find an expression for the total online social group membership M(t) at time t.

(b) Use the answer to part (a) to estimate the online social group membership midway through 2008.
M(3.5) = million members  At the start of 2005, an online social group had 1 million members. Since that time, new members joined at a rate of approximately
m(t) = 12t2 − 20t + 10 million members per year    (0 ≤ t ≤ 3.5)
where t is time in years since the start of 2005.

(a) Find an expression for the total online social group membership M(t) at time t.

(b) Use the answer to part (a) to estimate the online social group membership midway through 2008.
M(3.5) = million members  @Mathematics

anonymous · Answer

can anyone help me?