A 14 foot ladder is leaning on a wall, slowly sliding down. If the base of the ladder is sliding away from the wall at 1.3 ft/second, how fast is the top sliding vertically along the wall when the bottom of the ladder is 9 feet from the wall? @Calculus1

8 years agowe need a relation that has the legs of a right triangle in it id assume

8 years agothe pythag might be useful

8 years agowall^2 + floor^2 = 9 2w w' + 2f f' = 0 2w w' = -2f f' w' = -2f f'/2w w' = -f f'/w

8 years agowith that being done i got 16.6

8 years agow' = -f f'/w w' = -9 (1.3)/sqrt(14^2 - 9^2) = -1.091..

8 years agopyth. theorem c =16.6

8 years ago|dw:1319578396135:dw|

8 years agoi get a little over 10 for the wall height

8 years agoi got 10.7 so yea.... idk how to approach this problem .. is it like the other one ?

8 years agothey are all the same; once you have a relationship that ties it all together, its just a metter of fillin gin the pieces afterwards

8 years agoA balloon is being inflated at a rate of 10 cm3/sec. At what rate is the radius of the balloon changing when the radius is 20 cm?

8 years agoi got 1256 and its wrong

8 years agovolume and raduis need to be related

8 years ago\[V_{sphere}=\frac{4}{3}pi\ r^3\]right?

8 years agovolume = 4/3pi 3r^2

8 years agoyea thats what i qot

8 years ago\[V = \frac{4}{3}\pi\ r^3\] \[V' = 4\pi\ r^2\ r'\] \[\frac{V'}{4\pi\ r^2} = \ r'\]

8 years agoV' = 10, and r=20

8 years ago.002?

8 years agothats a good apporx yeah

8 years agoA small spherical balloon is being inflated at the rate of 30 cm3/sec. What is the volume of the balloon 45 seconds after inflation begins? do i jus multiply 30 and 45

8 years agoi would

8 years agoi now have to find the diameter of the balloon and ik diameter id r^2

8 years ago