Question

how would i solve: Find a real number, t, such that the line containing the points (8, 9) and (t, 4) has a slope of 3

Answer 1

use point slope formula y-9=3(x-8) [the 9 and 8 are from point (8,9) and the 3 is from the slope
simplify to get y=3x+15
Then plug in 4 for y and solve for the x

Answer 2

I did and I got -11/3=x, but when I type it into my homework it says it's wrong?

Answer 3

You should use y=3x-15
by the way you should use the slope formula
(9-4)/(8-t)=3 cross multiply
3(8-t)=5
finish it and you will get the correct t value.