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Mathematics
OpenStudy (anonymous):

Explain, in complete sentences, how you would completely factor 15x2 – 25x – 60 and check your factors for accuracy

7 years ago
OpenStudy (anonymous):

use decomposition whenever you want to factor a quadratic with a non-zero coefficient (in this case your coefficient is 15, the first number in the formula)

7 years ago
OpenStudy (anonymous):

in order to do this just follow these steps: --multiply the first and the last -> (15)(-60)= -900 --find 2 numbers that add up to the middle term ( -25) and make up - 900 -> in this case, (-45) and 20 then replace these 2 numbers for your (-25) variable -> 15x\[^{2}\]-45x + 20x -60 , note that that -45 + 20 = -25 and thus u have not changed the equation

7 years ago
OpenStudy (anonymous):

\[15x ^{2}-45x+20x-60\]

7 years ago
OpenStudy (anonymous):

from here just separate the equation into 2 equations with brackets, \[(15x ^{2} - 45) + (20x - 60)\] and then factor the numbers out to get a simplified version of the formula -> \[15x(x-3) + 20(x-3)\] ... note that you have common (x-3) as a common factor in there so you can then just factor the two out. -> \[(15x+20)(x-3)\] and then go ahead and reduce the 15x+20 or leave it as it is and ur done

7 years ago
OpenStudy (anonymous):

medal me please :)

7 years ago
OpenStudy (anonymous):

Thanks

7 years ago
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