Mathematics 25 Online
OpenStudy (anonymous):

How do I factor 8y^2 - 10xy / 4y? Please help me answer this question..

jimthompson5910 (jim_thompson5910):

$\Large \frac{8y^2 - 10xy}{4y}$ $\Large \frac{2y(4y - 5x)}{4y}$ $\Large \frac{2y(4y - 5x)}{2*2y}$ $\Large \frac{\cancel{2y}(4y - 5x)}{2*\cancel{2y}}$ $\Large \frac{4y - 5x}{2}$ So $\Large \frac{8y^2 - 10xy}{4y} = \frac{4y - 5x}{2}$

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