Question

How do I factor 8y^2 - 10xy / 4y? Please help me answer this question..

Answer 1

\[\Large \frac{8y^2 - 10xy}{4y}\]


\[\Large \frac{2y(4y - 5x)}{4y}\]


\[\Large \frac{2y(4y - 5x)}{2*2y}\]


\[\Large \frac{\cancel{2y}(4y - 5x)}{2*\cancel{2y}}\]


\[\Large \frac{4y - 5x}{2}\]


So \[\Large \frac{8y^2 - 10xy}{4y} = \frac{4y - 5x}{2}\]