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OpenStudy (anonymous):
Use the x-intercepts to find the intervals on which the graph of f is above and below the x-axis. f(x) = (x + 5)^2
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OpenStudy (anonymous):
I think you factor then graph y=X^2+10x+25 then graph
OpenStudy (anonymous):
\[(- \infty,5) and (5,\infty)\]
OpenStudy (anonymous):
nope oops\[(-\infty,-5)and(-5,\infty)\]
OpenStudy (anonymous):
Are they above or below the x-axis?
OpenStudy (anonymous):
Above the x axis.
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OpenStudy (anonymous):
Both?
OpenStudy (anonymous):
yeah. Graph it and see.
OpenStudy (anonymous):
The vertex touches the x axis at the point (-5,0) but never goes below it.
OpenStudy (anonymous):
Yes thus its an even multiplicity
OpenStudy (anonymous):
Thanks
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