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Mathematics 18 Online
OpenStudy (anonymous):

Verify the following identity: [tan^2(theta)+1] / [tan(theta)csc^2(theta)] Verify the following identity: [tan^2(theta)+1] / [tan(theta)csc^2(theta)] @Mathematics

OpenStudy (anonymous):

oh crap that's supposed to be an equation equaling to tan(theta).

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