Determine whether the following function is even, odd, or neither. Please show work.
f(x) = x^2/3 + x -1 Determine whether the following function is even, odd, or neither. Please show work.
f(x) = x^2/3 + x -1 @Mathematics

Question

Determine whether the following function is even, odd, or neither. Please show work. 
f(x) = x^2/3 + x -1 Determine whether the following function is even, odd, or neither. Please show work. 
f(x) = x^2/3 + x -1 @Mathematics

anonymous · Answer

a function is even when f(x) =f(-x)
it is odd when f(-x) = -f(x)
in other case neither odd nor even
X = 8 as a example
now f(-8) = 4 - 8 -1= -5
f(8) = 4+8-1 = 11
so it neigher satisfies any above conditions
hence it is neither odd nor even

anonymous · Answer

Did you mean to say neither? You wrote "neigher", I assume a typo?

anonymous · Answer

ya it is neither.. !!

anonymous · Answer

ok- so my answer to this question would be neither?

anonymous · Answer

yes!!, your answer is f(x) is neither odd nor even function

anonymous · Answer

ok great. Sorry- this stuff confuses me so much. Thank you for helping!

anonymous · Answer

welcome!!