Question

area under the curve y=4-x^2, y=0. (Calc 2 question)

Answer 1

are you asking
\[\int(4-x^2)dx\]
or
\[\int\limits_{0}^{0}(4-x^2)dx\]?

the information you are providing seems a bit odd.

Answer 2

im asking area under the curve y=4-x^2 bound by the line y=0. that would yeild an INT/limits from 1 to -1/(4-x^2)dx...I believe

Answer 3

Oh, I got yah know.
So, start by finding the zeros of 4-x^2 (these will be your limits)
-x^2=-4
x^2=4
x= 2;-2
\[\int\limits_{-2}^{2}4-x^2dx\]
\[\int\limits_{-2}^{2}4dx-\int\limits_{-2}^{2}x^2dx\]
\[4x-\frac{x^3}{3}\]
take it to the limits:
[4(2)-(2^3)/3]-[4(-2)-(-2^3)/3]=32/3