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40x^2-9x-9=0
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sometimes its just best to go to the quadratic formula
\[x=\frac{1}{2}(9\pm \sqrt{9^2-4(40)(-9)})\]
forgot a 40 in there
=(8x+3)(5x-3) =>x=-3/8 or x=3/5
the 1/2 = 1/80
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