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ODE: y'=x+y any solutions?
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y=-x-1 is a solution
good, but a more general solution would be with the constant attached right
but i spose i said "any" ;)
y'-y=x /*e^-x (ye^-x)'=xe^-x iintegral xe^-x=-e^-x(x+1)+C so y=-x-1+C/e^-x
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