Question

how do you write an equation in point-slope form with the slope of 3 and points (2,5) *really important question PLEASE answer it

Answer 1

point slope form, not slope intercept form

Answer 2

y-Py = m(x-Px)

Answer 3

they give you the slope and the (Px,Py)

Answer 4

:O
My bad. :/

Answer 5

'sok, they all look alike after wahile lol

Answer 6

y = mx + b

5 = 3(2) + b
5 = 6 + b
b = 5-6
b = -1

(0,-1)

Now,

\[(y_2-y_1)= m(x_2-x_1)\]

Answer 7

\[y-5 = 3 (x-2) \]

Answer 8

the equation of a line start by finding a slope, and all the other forms are but an algebraic manipulation of that:

given 2 points: (Px,Py) and (x,y) , slope is defined as the difference in the y values with respect to the difference in the x values:

so subtract the points and divide y by x

(x , y)
-(Px,Py)
-------
(x-Px,y-Py); slope, or m as it is so named, = y/x:

y-Py
---- = m ; from this we can get the "point slope" form
x-Px


y-Py = m(x-Px) ; and from this we can obtain the "slope intercept" form

y = mx + [-mPx+Py]

y = mx + c; if we split the slope back up into a rational form we can manipulate it into the "standard" form for the equation of a line:

y = (-a/b)x + c ; such that c is any constant, even c/b would be suitable

y = (-a/b)x + c/b

by = -ax + c

ax + by = c ; and from this we can get the "intercept form" of the line


ax by c
-- + -- = --
c c c


x y
--- + --- = 1 ; where c/a and c/b are the intercepts
c/a c/b