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Mathematics
OpenStudy (anonymous):

Find the derivative of (3sinX)/(5-2cosX)

OpenStudy (anonymous):

its a quotent rule :)

OpenStudy (anonymous):

I'll look that up. Thanks man, but could you please work this one out for me. I need to see the steps because I have 5 or 6 more to do.

OpenStudy (anonymous):

(5-2cosx)(3cosx)-(3sinx)(-2(-sinx)/ (5-2cosx)^2

OpenStudy (anonymous):

Thanks.

OpenStudy (anonymous):

sure

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