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OpenStudy (anonymous):
Find the derivative of (3sinX)/(5-2cosX)
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OpenStudy (anonymous):
its a quotent rule :)
OpenStudy (anonymous):
I'll look that up. Thanks man, but could you please work this one out for me. I need to see the steps because I have 5 or 6 more to do.
OpenStudy (anonymous):
(5-2cosx)(3cosx)-(3sinx)(-2(-sinx)/ (5-2cosx)^2
OpenStudy (anonymous):
Thanks.
OpenStudy (anonymous):
sure
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