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    				(1/7)(z+2)-(1/2)(z+3)=0 solve
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\[(\frac17)(z+2)-\frac12(z+3) = 0\]
2z + 4 - 7z - 21 = -5z -17
\[ \left\{\left\{z= -\frac{17}{5}\right\}\right\} \]
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