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3/((x-8)(x-3))=1/(x-8)+8(x-3)
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\[\frac{3}{(x-8)(x-3)}=\frac{1}{x-8}+\frac{8}{x-3}\]
\[\frac{3}{(x-8)(x-3)}-\frac{1}{x-8}-\frac{8}{x-3}=0\]
take the lcm = (x-8)(x-3)
And solve.! ^_^
i cant
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lol.
help?
yes, x = 70/9
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