Question

sqrt[3]{1+10x}-3=0

Answer 1

sqrt[3]{1+10x}-3=0

Answer 2

start with
\[\sqrt[3]{1+10x}=3\] then cube both sides to get
\[1+10x=3^3=27\]

Answer 3

\[\sqrt[3]{1+10x} = 3\]
\[1+10x = 27\]
\[10x = 27 - 1\]
\[10x = 26\]
\[x = \frac{26}{10}\]
\[x = \frac{13}{5}\]

Answer 4

Extending from satellite73 .....

10x = 26
\[ x= \frac {13} 5 \]