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Mathematics 19 Online
OpenStudy (anonymous):

sqrt[3]{1+10x}-3=0

OpenStudy (anonymous):

sqrt[3]{1+10x}-3=0

OpenStudy (anonymous):

start with \[\sqrt[3]{1+10x}=3\] then cube both sides to get \[1+10x=3^3=27\]

OpenStudy (saifoo.khan):

\[\sqrt[3]{1+10x} = 3\] \[1+10x = 27\] \[10x = 27 - 1\] \[10x = 26\] \[x = \frac{26}{10}\] \[x = \frac{13}{5}\]

OpenStudy (anonymous):

Extending from satellite73 ..... 10x = 26 \[ x= \frac {13} 5 \]

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