What's Wrong With This Answer? 1 sec, posting the attached img. What's Wrong With This Answer? 1 sec, posting the attached img. @Mathematics
I double checked this, and I still don't see where the heck I went wrong.
did you take the derivaitve of the e^-x twice
i think you did
when you applied the product rule
No because that second -ve sign comes from the cos
because (cosx)' = -sinx
looks good to me if this is on line work, you probably have to write sin(pix) rather than sinpix
Aw these stupid technical errors.
Why is the derivative log(2) in that link instead of ln(2)?
read the fine print...log is the natural log
the large print giveth and the small print taketh away
that wolfram link is not the question you were asked
If you mean the wolfram solution, it is ln(2) "log (x) is the natural logarithm"
Join our real-time social learning platform and learn together with your friends!