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Mathematics
OpenStudy (anonymous):

What's Wrong With This Answer? 1 sec, posting the attached img. What's Wrong With This Answer? 1 sec, posting the attached img. @Mathematics

OpenStudy (anonymous):

OpenStudy (anonymous):

I double checked this, and I still don't see where the heck I went wrong.

OpenStudy (anonymous):

did you take the derivaitve of the e^-x twice

OpenStudy (anonymous):

i think you did

OpenStudy (anonymous):

Where?

OpenStudy (anonymous):

when you applied the product rule

OpenStudy (anonymous):

No because that second -ve sign comes from the cos

OpenStudy (anonymous):

because (cosx)' = -sinx

OpenStudy (anonymous):

looks good to me if this is on line work, you probably have to write sin(pix) rather than sinpix

OpenStudy (anonymous):

Aw these stupid technical errors.

OpenStudy (anonymous):

Why is the derivative log(2) in that link instead of ln(2)?

OpenStudy (zarkon):

read the fine print...log is the natural log

OpenStudy (anonymous):

the large print giveth and the small print taketh away

OpenStudy (anonymous):

that wolfram link is not the question you were asked

OpenStudy (anonymous):

If you mean the wolfram solution, it is ln(2) "log (x) is the natural logarithm"

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