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OpenStudy (anonymous):
What's Wrong With This Answer?
1 sec, posting the attached img.
What's Wrong With This Answer?
1 sec, posting the attached img.
@Mathematics

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OpenStudy (anonymous):
OpenStudy (anonymous):
I double checked this, and I still don't see where the heck I went wrong.

OpenStudy (anonymous):
did you take the derivaitve of the e^-x twice

OpenStudy (anonymous):
i think you did

OpenStudy (anonymous):
Where?

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OpenStudy (anonymous):
when you applied the product rule

OpenStudy (anonymous):
No because that second -ve sign comes from the cos

OpenStudy (anonymous):
because (cosx)' = -sinx

OpenStudy (anonymous):
looks good to me if this is on line work, you probably have to write
sin(pix) rather than sinpix

OpenStudy (anonymous):
Aw these stupid technical errors.

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OpenStudy (anonymous):
Why is the derivative log(2) in that link instead of ln(2)?

OpenStudy (zarkon):
read the fine print...log is the natural log

OpenStudy (anonymous):
the large print giveth and the small print taketh away

OpenStudy (anonymous):
that wolfram link is not the question you were asked

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OpenStudy (anonymous):
If you mean the wolfram solution, it is ln(2)
"log (x) is the natural logarithm"

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