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OpenStudy (anonymous):
how many molecules of NH3 from 2.26*10^-4g of H_2 how many molecules of NH3 from 2.26*10^-4g of H_2 @Chemistry
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OpenStudy (anonymous):
3H2+N2→2NH3 2 moles of ammonia for every 3 moles of hydrogen 4.54*10^19 molecules of ammonia.
OpenStudy (anonymous):
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