y=(cosx)/(1-sinx) use product rule. I got (1)/(1+sinx) but I need verification
quotent rule
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yeah I ment quotient rule, my bad
its wrong wait
(1-sinx)(-sinx)-(cosx)(-cosx)/(1-sinx)^2
you always have to square the denominator don't forget
yeah but we have to simplify using the trig identities
oh
\[\frac{1}{1-\sin(x)}\]
yeah so I'm still uncertain
how did you get that @zarkon?
just simplify alvinstifla's solution
how exactly? please show me steps.
\[\frac{(1-\sin(x))(-\sin(x))-(\cos(x))(-\cos(x))}{(1-\sin(x))^2}\] \[=\frac{-\sin(x)+\sin^2(x)+\cos^2(x)}{(1-\sin(x))^2}\] \[=\frac{-\sin(x)+1}{(1-\sin(x))^2}\] \[=\frac{1-\sin(x)}{(1-\sin(x))^2}\] \[=\frac{1}{1-\sin(x)}\]
so how did you end up having 1-sinx as the denominator?
\[\frac{a}{a^2}=\frac{1}{a}\]
oh okay so you had (1-sinx)/(1-sinx)(1-sinx) and you cancelled (1-sinx) out to leave you with (1-sinx( right
yes..you can say it that way
sorry I had some brain fart or something. For some reason I was changing the signs. Thank you lots Zarkon! do you think you can help me on one more problem?
Please go through it.
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