An electron of mass 9.11×10^−31kg leaves one end of a TV picture tube with zero initial speed and travels in a straight line to the accelerating grid, which is a distance 2.65cm away. It reaches the grid with a speed of 3.20×10^6 m/s . The accelerating force is constant.

How do i find the acceleration?
An electron of mass 9.11×10^−31kg leaves one end of a TV picture tube with zero initial speed and travels in a straight line to the accelerating grid, which is a distance 2.65cm away. It reaches the grid with a speed of 3.20×10^6 m/s . The accelerating force is constant.

How do i find the acceleration?
@Physics

Question

An electron of mass 9.11×10^−31kg  leaves one end of a TV picture tube with zero initial speed and travels in a straight line to the accelerating grid, which is a distance 2.65cm  away. It reaches the grid with a speed of 3.20×10^6 m/s . The accelerating force is constant.

How do i find the acceleration?
 An electron of mass 9.11×10^−31kg  leaves one end of a TV picture tube with zero initial speed and travels in a straight line to the accelerating grid, which is a distance 2.65cm  away. It reaches the grid with a speed of 3.20×10^6 m/s . The accelerating force is constant.

How do i find the acceleration?
 @Physics

anonymous · Answer

I guess you can use the formula v^2=v'(initial speed)^2 + 2ad

anonymous · Answer

so if i solve for acceleration in that equation its
a=v^2-v'^2/2d
right?

anonymous · Answer

yeah you are right

anonymous · Answer

ok i am doing 
a = (3.2x10^6m/s)^2/(2x2.65cm)
and i am getting 1.932075, but that answer is wrong in the homework software i am using...what am i doing wrong?

anonymous · Answer

2.65cm -> 0.0265m

anonymous · Answer

oh man i didnt even notice that, now i got the right answer:)
thanks!