Question

how do you expand 5(3x-1)^2 ?

Answer 1

\[=5(9x^2-6x+1)=45x^2-30x+5\]

Answer 2

square the parens then distribute the 5

Answer 3

A simple approach if you're just learning algebra is to first expand the brackets:
\[5(3x-1){^2}\]\[=5(3x-1)(3x-1)\]
Then go along the equation and multiply out each term, remembering to distribute the 5:
\[=5\times(3x \times 3x) - 5\times 1\times 3x - 5\times 1 \times 3x + 5\times 1 \times 1\]
Now begin to group like terms and simplify:
\[=5\times 9x{^2} - 10\times 3x + 5\]\[=45x{^2}-30x+5\]

Answer 4

First step = 5(9x^2-3x-3x+1)
Second step =5(9x^2-6x+1)
Third step = 45x^2-30x+5

Answer 5

thanks !