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Mathematics 28 Online
OpenStudy (anonymous):

5^6x+1 = 25

OpenStudy (anonymous):

5^(6x + 1) = 25 ?

OpenStudy (anonymous):

5^(6x + 1) = 5^2 6x + 1 = 2 6x = 1 x = 1/6

OpenStudy (anonymous):

ufffffffffff coolsector allow them to do it by their own

OpenStudy (anonymous):

is the answer not 1/2

OpenStudy (anonymous):

\[5^6x+1 = 25\]

OpenStudy (anonymous):

is this ur question?

OpenStudy (anonymous):

Nope that isn't the question: 5^(6x+1)=25

OpenStudy (anonymous):

how do u know @ rld yes simon is rld right

OpenStudy (anonymous):

\[5^{6x+1}=25\]

OpenStudy (anonymous):

ok then how to start this one

OpenStudy (anonymous):

me?

OpenStudy (anonymous):

yes u simon

OpenStudy (anonymous):

Sheg r u a teacher?

OpenStudy (anonymous):

ln?

OpenStudy (anonymous):

yeah u can say

OpenStudy (anonymous):

You must make both sides have the same bases

OpenStudy (anonymous):

but still a student

OpenStudy (anonymous):

\[5^{1/6}=25\]

OpenStudy (anonymous):

Both should be a base of 5

OpenStudy (anonymous):

no simon don't copy from above

OpenStudy (anonymous):

ok rld you explain this one to him / her

OpenStudy (anonymous):

5^2=25 since 5*5=25

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

1/2^6 = 5

OpenStudy (anonymous):

so 5^(6x+1)=5^2 so 6x+1=2 Then you solve for x simple as that

OpenStudy (anonymous):

so what is the answer

OpenStudy (anonymous):

solve it

OpenStudy (anonymous):

do i divide by 5 to begin with to get rid of the 5 on the left hand side

OpenStudy (anonymous):

no as on both sides we had common base so the power of both se sides will be equal 5^(6x+1) = 5^2 so, 6x+1 = 2

OpenStudy (anonymous):

SOLVE FOR X: 6x+1=2 BTW what grade r u in?

OpenStudy (anonymous):

hey rld wt do u do

OpenStudy (anonymous):

im 16

OpenStudy (anonymous):

k whr from?

OpenStudy (anonymous):

ireland

OpenStudy (anonymous):

simon whr u r solve for x

OpenStudy (anonymous):

ok m from India and u RLD

OpenStudy (anonymous):

cool

OpenStudy (anonymous):

I figured u were from India. I am from Canada

OpenStudy (anonymous):

how u figured it out @ rld

OpenStudy (anonymous):

Alot of indians on here

OpenStudy (anonymous):

we are everywhere nothing new hahahaaha

OpenStudy (anonymous):

The way you spoke english. I had a indian tutor

OpenStudy (anonymous):

simon solve this one 6x+1 = 2

OpenStudy (anonymous):

Well there are a billion indians in india!!!!

OpenStudy (anonymous):

how old u r

OpenStudy (anonymous):

Not tellin you :)

OpenStudy (anonymous):

1/6

OpenStudy (anonymous):

ok so i can figure out that u r a girl

OpenStudy (anonymous):

ok great simon u did it by ur own right keep it up buddy

OpenStudy (anonymous):

but my text book says the answer is 1/2

OpenStudy (anonymous):

RLD wht do u say simon can do better right

OpenStudy (anonymous):

Pretty close!

OpenStudy (anonymous):

the text book must be wrong

OpenStudy (anonymous):

@ simon sumtimes we have printing errors too have confident on thyself

OpenStudy (anonymous):

what did the textbook say?

OpenStudy (anonymous):

so in which standard do u study @ Simon & RLD

OpenStudy (anonymous):

What is standard?

OpenStudy (anonymous):

means class college or, school

OpenStudy (anonymous):

Well simon is in grade 10

OpenStudy (anonymous):

u guys there

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

do u attend college or school @ Simon & RLD

OpenStudy (anonymous):

I attend college!

OpenStudy (anonymous):

ok what do u study?

OpenStudy (anonymous):

Well i am getting a B.A. with a major in math

OpenStudy (anonymous):

OMG...in which year

OpenStudy (anonymous):

i studt chemistry boilogy and mths

OpenStudy (anonymous):

Still in first year

OpenStudy (anonymous):

so shall i guess u ppls age

OpenStudy (anonymous):

simon has already said 16yrs old RLD is minimum 17 yrs old Maximum 19 yrs old means its range

OpenStudy (anonymous):

But I will be able to finish like in year and a half since I attended a diff college and am transferring all those credits

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

|dw:1319741280988:dw|

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