Mathematics
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OpenStudy (anonymous):
5^6x+1 = 25
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OpenStudy (anonymous):
5^(6x + 1) = 25 ?
OpenStudy (anonymous):
5^(6x + 1) = 5^2
6x + 1 = 2
6x = 1
x = 1/6
OpenStudy (anonymous):
ufffffffffff coolsector allow them to do it by their own
OpenStudy (anonymous):
is the answer not 1/2
OpenStudy (anonymous):
\[5^6x+1 = 25\]
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OpenStudy (anonymous):
is this ur question?
OpenStudy (anonymous):
Nope that isn't the question:
5^(6x+1)=25
OpenStudy (anonymous):
how do u know @ rld
yes simon is rld right
OpenStudy (anonymous):
\[5^{6x+1}=25\]
OpenStudy (anonymous):
ok
then how to start this one
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OpenStudy (anonymous):
me?
OpenStudy (anonymous):
yes u simon
OpenStudy (anonymous):
Sheg r u a teacher?
OpenStudy (anonymous):
ln?
OpenStudy (anonymous):
yeah u can say
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OpenStudy (anonymous):
You must make both sides have the same bases
OpenStudy (anonymous):
but still a student
OpenStudy (anonymous):
\[5^{1/6}=25\]
OpenStudy (anonymous):
Both should be a base of 5
OpenStudy (anonymous):
no simon don't copy from above
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OpenStudy (anonymous):
ok rld you explain this one to him / her
OpenStudy (anonymous):
5^2=25 since 5*5=25
OpenStudy (anonymous):
yes
OpenStudy (anonymous):
1/2^6 = 5
OpenStudy (anonymous):
so 5^(6x+1)=5^2
so 6x+1=2
Then you solve for x simple as that
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OpenStudy (anonymous):
so what is the answer
OpenStudy (anonymous):
solve it
OpenStudy (anonymous):
do i divide by 5 to begin with to get rid of the 5 on the left hand side
OpenStudy (anonymous):
no as on both sides we had common base so the power of both se sides will be equal
5^(6x+1) = 5^2
so,
6x+1 = 2
OpenStudy (anonymous):
SOLVE FOR X: 6x+1=2
BTW what grade r u in?
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OpenStudy (anonymous):
hey rld wt do u do
OpenStudy (anonymous):
im 16
OpenStudy (anonymous):
k whr from?
OpenStudy (anonymous):
ireland
OpenStudy (anonymous):
simon whr u r solve for x
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OpenStudy (anonymous):
ok m from India
and u RLD
OpenStudy (anonymous):
cool
OpenStudy (anonymous):
I figured u were from India. I am from Canada
OpenStudy (anonymous):
how u figured it out @ rld
OpenStudy (anonymous):
Alot of indians on here
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OpenStudy (anonymous):
we are everywhere nothing new hahahaaha
OpenStudy (anonymous):
The way you spoke english. I had a indian tutor
OpenStudy (anonymous):
simon solve this one
6x+1 = 2
OpenStudy (anonymous):
Well there are a billion indians in india!!!!
OpenStudy (anonymous):
how old u r
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OpenStudy (anonymous):
Not tellin you :)
OpenStudy (anonymous):
1/6
OpenStudy (anonymous):
ok so i can figure out that u r a girl
OpenStudy (anonymous):
ok great simon u did it by ur own right keep it up buddy
OpenStudy (anonymous):
but my text book says the answer is 1/2
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OpenStudy (anonymous):
RLD wht do u say simon can do better right
OpenStudy (anonymous):
Pretty close!
OpenStudy (anonymous):
the text book must be wrong
OpenStudy (anonymous):
@ simon sumtimes we have printing errors too have confident on thyself
OpenStudy (anonymous):
what did the textbook say?
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OpenStudy (anonymous):
so in which standard do u study @ Simon & RLD
OpenStudy (anonymous):
What is standard?
OpenStudy (anonymous):
means class college or, school
OpenStudy (anonymous):
Well simon is in grade 10
OpenStudy (anonymous):
u guys there
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OpenStudy (anonymous):
yes
OpenStudy (anonymous):
do u attend college or school @ Simon & RLD
OpenStudy (anonymous):
I attend college!
OpenStudy (anonymous):
ok what do u study?
OpenStudy (anonymous):
Well i am getting a B.A. with a major in math
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OpenStudy (anonymous):
OMG...in which year
OpenStudy (anonymous):
i studt chemistry boilogy and mths
OpenStudy (anonymous):
Still in first year
OpenStudy (anonymous):
so shall i guess u ppls age
OpenStudy (anonymous):
simon has already said 16yrs old
RLD is minimum 17 yrs old Maximum 19 yrs old
means its range
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OpenStudy (anonymous):
But I will be able to finish like in year and a half since I attended a diff college and am transferring all those credits
OpenStudy (anonymous):
ok
OpenStudy (anonymous):
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