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If f(x)=xe^(9x), find the largest interval on which f(x) is concave upward.
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did you find f'' and set it =0
I don't know how to find it...
\[f'(x)=e^{9x}+9xe^{9x}\]\[f''(x)=9e^{9x}+9e^{9x}+81xe^{9x}=18e^{9x}+81xe^{9x}=0\]
product rule (f*g)'=f'g+g'f
-2/9. Thank you!!!
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