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OpenStudy (anonymous):
What is the limit of [x^3-2x^2+sin(x)]/(x^2-x) as x approaches infinity ?
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OpenStudy (anonymous):
infinity
OpenStudy (anonymous):
can you explain why? *how you got the answer?
OpenStudy (anonymous):
well the higher power of x on top is 3 and on the bottom is 2....so if u think about it, as x goes to infinity, the top goes quicker than the bottom...therefore infinity
OpenStudy (anonymous):
oh thanks
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