Question

Find the equation of the tangent line to (x^2-4)y = 8 at the point (-2,1)

Answer 1

the slope of the tangent line is f'(-2)

Answer 2

the equation in point slope form is then:

y-1= f'(-2)(x+2)

Answer 3

if you need slope intercept then it goes:

y = f'(-2)x -f'(-2)(-2)+1

Answer 4

(x^2-4)y = 8

is that y and exponent by chance?