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If x*x + 2x - 35 = 0, then x = ?
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x = -7 or x = 5
If x*x + 2x - 35 = 0, then x = ?
either x=-7 or x=5
x^2 + 2x -35 = 0 x^2+7x - 5x - 35 = 0 x(x+7) -5(x+7) = 0 (x+7)(x-5) =0 x = -7 x = 5
solving it by middle term breaking
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it's a binomial that you have to factor. x^2 +2x-35=0 (x+7)(x-5) then you set them equal to 0. so x=-7 or x=5
(1)x*x + (2)x + (-35) = 0 a = 1 b = 2 c = -35 (-b +/- d)/2a d*d = b*b - 4ac x = -5, 7
hero,s method is rite
-7 and 5 u r wrong fibonacci girl
check again
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me?
yes lol :)
my ans is rite
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