Question

add and simplify, if possible x^2+13x/x^2-7x + x^2-8x/x^2-7x

Answer 1

\[\Large \frac{x^2+13x}{x^2-7x} + \frac{x^2-8x}{x^2-7x}\]



\[\Large \frac{x^2+13x+x^2-8x}{x^2-7x}\]



\[\Large \frac{2x^2+5x}{x^2-7x}\]



So \[\Large \frac{x^2+13x}{x^2-7x} + \frac{x^2-8x}{x^2-7x}=\frac{2x^2+5x}{x^2-7x}\]

Answer 2

x(2x+5)/x(x-7)=(2x+5)/(x-7)