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show your work please i do not get it at "ALL"! x2 - 3|x - 2| - 4x = - 6
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\[\text{if } x-2>0 \text{ then} |x-2|=x-2\] \[\text{if } x-2<0 \text{ then} |x-2|=-(x-2)\]
so we have two cases
solve: \[x^2-3(x-2)-4x=-6\] \[x^2-3(-(x-2))-4x=-6\]
you have two cases so two equations to solve
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