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Mathematics 17 Online
OpenStudy (anonymous):

the length of a rectangle is fixed at 25 cm. What widths will make the parameter greater than 88 cm?

jimthompson5910 (jim_thompson5910):

P = 2W+2L P = 2W+2(25) P = 2W+50 So the perimeter expression is 2W+50 Since we want the perimeter to be greater than 88, this means that P > 88 and 2W+50 > 88 2W > 88-50 2W > 38 W > 38/2 W > 19 So the width must be greater than 19 cm

hero (hero):

perimeter, not parameter

OpenStudy (anonymous):

named after a guy named Peri who had a meter.

OpenStudy (anonymous):

so would two meters be pair a meters?

OpenStudy (anonymous):

or two medics?

hero (hero):

I wouldn't worry about the origins of "perimeter" at the moment.

hero (hero):

Just know that "perimeter" means "the distance around something"

hero (hero):

In this case, it means the distance around a rectangle

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