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rtex of the quadratic equation: y = 2x2 + 12x − 4.
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rtex?
vertex
2(x^2 + 6x-2)=0 x^2+6x-2=0 x = (-6+(36+8)^(1/2) / 2 x= some complex
what is a vertex ?
yes i need coordinates
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let the vertex=(x,y)
then x=-b/za, according to y=ax^2+bx+c
x=-b/2a
so the answer is (-3,-22), do you understand?
f'(x)=2(2x+6)=0 x = -3 y = -22 f''(x)=4 >0 hence local minimum (-3,-22) ??
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yes thanks
yes ,the minimum is -22
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