Find the equation of the line tangent to the graph of the given function at the point with the indicated x-coordinate.
f(x)= sqrt(x) + 1/sqrt(x)+5; x = 4
y=

need help with calculus! I dont seem to be getting very far with this problem :/

Question

Find the equation of the line tangent to the graph of the given function at the point with the indicated x-coordinate.
f(x)= sqrt(x) + 1/sqrt(x)+5; x = 4
y=

need help with calculus! I dont seem to be getting very far with this problem :/

anonymous · Answer

plug it in?

mimi_x3 · Answer

Find the derivative first, then find m by substituting x=4 in.

Then substitute m in 

y-y1 = m(x-x1)

anonymous · Answer

so find the slope at the given point by taking the derivitive.
1/(2sqrtx)-x^(-3/2)/2
plug in x=4