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OpenStudy (anonymous):
1 over (b - 1) + 3 over (1 - b) can someone explain how to do this problem please? :)
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OpenStudy (anonymous):
Multiply the second fraction by -1/(-1) Then you will have 2 fractions with the same denominator and you can add numerators (1-3)/(b-1)=-2/(b-1) or 2/(1-b)
OpenStudy (anonymous):
1/(b-1) + 3/(1-b) =1/(b-1) - 3/(b-1) = -2/(b-1)
OpenStudy (anonymous):
=2/(1-b)
OpenStudy (anonymous):
thanks!
OpenStudy (anonymous):
you are welcome
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