need help with this equation
5/(4 ) (3x-1/2)-2/(3 ) <7/3
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OpenStudy (anonymous):
When you are solving and you have denominators, it is best to multiply every term by the least common denominator--- it will get rid of all denominators for you..
OpenStudy (anonymous):
Is the 2 under all of 3x - 1 or just under the 1?
OpenStudy (anonymous):
5 over 4 times 3x - 1/2 - 2/3 is less than 7 over 3
OpenStudy (anonymous):
So the least common denominator is 12 - so multiply every term by 12.
OpenStudy (anonymous):
@Blexting only under the 1
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according to my text from the chapter the 7/3 is to be done after I get the first part done
OpenStudy (anonymous):
90x - 15 - 16 < 56
90x - 31 < 56
90x < 87
x < 87/90 (I don't like the answer either)
OpenStudy (anonymous):
so it should look like 90x-15-16 < 7/3
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OpenStudy (anonymous):
If you multiply one of the terms by 24 you have to do it to all of them including the 7/3
OpenStudy (anonymous):
No.. that would not be correct.. it has to be done to everyterm.
90x - 15 - 16 < 56
OpenStudy (anonymous):
^he is right
OpenStudy (anonymous):
90x-31<56
OpenStudy (anonymous):
then times the the two denomanators 3x24
so I would have 90x - 15 - 16 < 72
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OpenStudy (anonymous):
gosh I am confused LMAO
OpenStudy (anonymous):
90x<87 x would be a decimal
OpenStudy (anonymous):
my instructor is a douch
OpenStudy (anonymous):
so I got 0.966666
OpenStudy (anonymous):
Above you had 72... it was 24(7/3) so 3 goes into 24 8 times and then time 7 is 56
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OpenStudy (anonymous):
remember, it is less than, not equal too
OpenStudy (anonymous):
therefore x= .966 or less
OpenStudy (anonymous):
Alright?
OpenStudy (anonymous):
so the solution set would be {x|x< .966}
OpenStudy (anonymous):
yes
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OpenStudy (anonymous):
THX to both of you I have one more problem if u have time...
OpenStudy (anonymous):
alright, but can i get a medal?
OpenStudy (anonymous):
it is the elimination method
OpenStudy (anonymous):
of course
how do i do that
OpenStudy (anonymous):
click good anwser for one of my anwsers
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OpenStudy (anonymous):
thankyou
OpenStudy (anonymous):
5x+5y= -11
7x-2y=19
OpenStudy (anonymous):
Now I will explain the Elimination method, to see if it helps you
OpenStudy (anonymous):
I get x=1.62
OpenStudy (anonymous):
I could not get Y cuzz i think x is wrong
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OpenStudy (anonymous):
When adding two equations, you basically add all parts of them. Say you had the equations:
5x + 5y = -11
7x-2y= 19
OpenStudy (anonymous):
so 12x + 3y= 8
OpenStudy (anonymous):
I have not had any problems using it with other problems i just did not like the answer I got for X
OpenStudy (anonymous):
12x + 3y = 8.
OpenStudy (anonymous):
If you have those two equation - you have to eliminate one of the variables.. so multiply the first by 2 and the second by 5
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OpenStudy (anonymous):
2(5x - 5y = 11)
5(7x - 2y = 19)
OpenStudy (anonymous):
elimination method is when you elou to cancel out on variable
OpenStudy (anonymous):
10x - 10y = 55
35x - 10y = 95
OpenStudy (anonymous):
Oops 10x + 10y = 55
35x - 10y = 95
OpenStudy (anonymous):
thats what I got blexting
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OpenStudy (anonymous):
Add them up
45x = 150
OpenStudy (anonymous):
x = 3 1/3
OpenStudy (anonymous):
the 11 is a negative
OpenStudy (anonymous):
OOPS.. you are correct.
OpenStudy (anonymous):
10x + 10y = -55
35x - 10y = 95
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OpenStudy (anonymous):
45x = 40
x = 40/45
x = 8/9
OpenStudy (anonymous):
i got 73/45
OpenStudy (anonymous):
ohhh ilike ur answer better then mine
OpenStudy (anonymous):
5x + 5y = -11
5(8/9) + 5y = -11
OpenStudy (anonymous):
40/9 + 5y = -11
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OpenStudy (anonymous):
ok os not iplug 8/9 into
OpenStudy (anonymous):
4 4/9 + 5y = -11
5y = -15 4/9
OpenStudy (anonymous):
but i still have a fraction how does that solve
OpenStudy (anonymous):
I would do this instead.
OpenStudy (anonymous):
5(8/9) + 5y = -11
Multiply every term by 9... it gets rid of denominators
40 + 45y = -99
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OpenStudy (anonymous):
45y = -139
OpenStudy (anonymous):
y = -3 4/45
OpenStudy (anonymous):
oh lord
OpenStudy (anonymous):
well thx for all ur help my assignment ti lto mor rowil tomorrow so I will keep all ur advice in mind I could not have figured it out hithout both of ur help!!!!!