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Find the perimeter of a rectangular object which has a length of √(75) feet and a width of √(48) feet
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\[18\sqrt{3}\]
Can you please explain, in complete sentences, how you arrived at the answer and give the final solution in simplified radical form.
The perimeter of a rectangle is 2a+2b where a and b are the sides So 2\[2\sqrt{75}+2\sqrt{48}=2\sqrt{3*25}+2\sqrt{3*16}\] \[=2*5*\sqrt{3}+2*4*\sqrt{3}=18\sqrt{3}\]
What items around the house would be this ?
Andras come back! haha
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For this it is easier to think of \[\sqrt{75}=8.66 and \sqrt{48}=6.93\]
I am European so I count in meters and cm. 8.66feet= 264cm 6.93feet=211 cm That is a bed I guess
double bed
or a big cupboard
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