Find the perimeter of a rectangular object which has a length of √(75) feet and a width of √(48) feet

Question

Find the perimeter of a rectangular object which has a length of √(75)  feet and a width of √(48) feet

anonymous · Answer

$$18\sqrt{3}$$

anonymous · Answer

Can you please explain, in complete sentences, how you arrived at the answer and give the final solution in simplified radical form.

anonymous · Answer

The perimeter of a rectangle is 2a+2b where a and b are the sides
So 2$$2\sqrt{75}+2\sqrt{48}=2\sqrt{3*25}+2\sqrt{3*16}$$
$$=2*5*\sqrt{3}+2*4*\sqrt{3}=18\sqrt{3}$$

anonymous · Answer

What items around the house would be this ?

anonymous · Answer

Andras come back! haha

anonymous · Answer

For this it is easier to think of 
$$\sqrt{75}=8.66 and \sqrt{48}=6.93$$

anonymous · Answer

I am European so I count in meters and cm. 8.66feet= 264cm
6.93feet=211 cm
That is a bed I guess

anonymous · Answer

double bed

anonymous · Answer

or a big cupboard