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Find four consecutive integers such that the sum of the second and the fourth is 132. Find four consecutive integers such that the sum of the second and the fourth is 132. @Mathematics
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64, 65, 66, 67
Four consecutive numbers are x, x + 1, x + 2, x + 3
so the 2nd one is x + 1 the 4th one is x + 3
so x + 1 + x + 3 = 132 2x + 4 = 132 2x = 128 x = 64 so the numbers are 64,65,66,67
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