The length of a rectangle is twice the width. If the length is increased by 4 inches and the width is diminished by 1 inch, a new rectangle is formed whose perimeter is 198 inches. Fine the dimensions of the original rectangle.

Question

The length of a rectangle is twice the width.     If the length is increased by 4 inches and the width is diminished by 1 inch, a new rectangle is formed whose perimeter is 198 inches.     Fine the dimensions of the original rectangle.

anonymous · Answer

width = x
length = 2x

If....
length 2x + 4
width x - 1

then
L + w + L + w = 198
2x + 4 + x - 1 + 2x + 4 + x - 1 = 198
6x + 6 = 198
6x = 192
x = 32

width 32
length 64

anonymous · Answer

Length = 32 in
Width = 16 in

anonymous · Answer

l=2w
l+4 + 2(w+1)=198 
l + 4 + 2w +2 = 198
     -4                    -4
l +2w +2 = 194
            -2    -2
l +2w= 192
    /2       /2
l +w= 96
l= 48 w= 24

anonymous · Answer

$$\{L=2w,2(L+4)+2(w-1)=198\} $$$$\{L=64,w=32\} $$