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OpenStudy (anonymous):
a^2+1^2=j^2, sovle for a
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OpenStudy (anonymous):
(j-a)(j+a) = 1
OpenStudy (anonymous):
Thanks :)
OpenStudy (anonymous):
If you are to solve for a then you would have a^2 = j^2 - 1 a = +-sqrt(j^2 - 1)
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