For questions 1-2, apply the quadratic formula to find the roots of the given function, and then graph the function. 1. (6 points) 0 = 3x^2 + 18x + 22 2. (6 points) 0 = -2x^2 + 8x - 3
1) x= [- 18 +- sqrt(18^2 - 4*3*22) ]/(2*3) x=(-18+-7.7459)/6 2) x= [-8 +- sqrt(8^2-4*-2*-3)]/(2*-2) x= (-8 +- 6.3245)/(-4) that is your answer!
dont i get 2 ys and 2 xs to graph?
yes! look at the '+-'. Just make math to get it!
im sorry i dont understand these ]: or the way you put it.
first you calculate using '+'. you find first x. then calculate using '-' and you get the second x!
x1=(-18+7.7459)/6 x2=(-18-7.7459)/6
um.....ok....
y =0 in both case because to their x values, the function value is zero. Thats x is called as zeros of function
but im getting \[x \approx-1.71,-4.29\]
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