Question

Perform the division. Assume no division by 0

x^2-16
------
x+4

Answer 1

\[x ^{2} -16 will break into (x+4)(x-4) and x+4 will \cancel out \in numerator and denominator\]

Answer 2

so whats the answer?

Answer 3

x =4 , because in numerator x-4=0 is remaining

Answer 4

got it?

Answer 5

so ii input 4 back into the equation in place of x and red it?

Answer 6

redo it*

Answer 7

tell me actually what does the question actually demand