Question

find the zeros/ complete the square 2x^2 + x - 5

Answer 1

\[2x^2+x=5\]
\[x^2+\frac{1}{x}x=\frac{5}{2}\]
\[(x+\frac{1}{4})^2=\frac{5}{2}+\frac{1}{16}=\frac{41}{16}\]
\[x+\frac{1}{4}=\pm\sqrt{41}{4}\]
\[x=\frac{-1\pm\sqrt{41}}{4}\]