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solve the equation ((7t+14)/(2t2+5t−12))+(1/(t+4))=(4/(2t−3)) i already know the answer i just need to know how to get it
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opps had a mistake let me repost it
putz!
((7t+14)/(2t^2+5t−12))+(1/(t+4))=(4/(2t−3))
i was considered that! =)
good :)
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i found t= 9/12 its correct? If it is, i wrote how i found..
i got t=1 but i cant remember how i got it and i gotta practice for mt test.
im wrong!
-_- i wish i could remember...
\o/
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i was forgetting the 2 on first denominator!
you can rewrite the first denominaotr as 2(t-1.5)(t+4) so multiplying both sides by 2(t-1.5)(t+4) and solving to t we get t=1!
ah! we need to rewrite (2t-3) as 2(t-1.5)
(7t+14) +2(t-1.5) -4(t+4)= 0 t=1
i got it 5t-5=0 thus making t=1
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thanks though!
you're welcome
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