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Mathematics
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Suppose we want to seat 3 men and 3 women in a row of six chairs. In how many ways can we seat these people if all the women must sit together but no woman sits on the end seats?
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can someone just check my answer i got 72 ways
you can seat mwwwmm or mmwwwm
and then x6 ways to seat each man and x 6 ways to seat each woman
36 WAYS FOR EACH OF THE two configurations you quoted - so thats 2 * 36 = 72
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