Question

(3x+2)^2+5(2x-3)+6=0

Answer 1

let y = 3x + 2

y^2 + 5y + 6 = 0
(y + 2)(y + 3) = 0
y = -2 or y = -3

now substitute 3x + 2 in for the y
3x + 2 = -2 or 3x + 2 = -3
3x = -4 or 3x = -5
x = -4/3 x = -5/3