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let f(x)=x/(x-2) . find a function y=g(x) so that (f°g)(x)=3x g(x)= ?? anybody can help??
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there is a catch here, x can't be 3. but otherwise the solution is easy
actually i don't understand the whole thing
let \[g(x) = y\] so, \[f(g(x)) = 3x \Rightarrow f(y) = 3x \Rightarrow \frac{y}{y-2} = 3x\] which gives \[y = \frac{6x}{3x-1}\] Hence \[g(x) = \frac{6x}{3x -1 }\] for a check, just plug in the f(g(x)) and see it equals 3x, but remember \[x \neq \frac{1}{3}\]
yes, sure !! thank you
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