Question

Find two numbers whose product is 15 such that one of the numbers is 7 more then 4 time the other number.

Answer 1

xy=15
x+7=4y

solve system

Answer 2

x + y = 15
y = 15 - x
7 + 4y = x

7 + 4(15 - x) = x
67 - 4x = x
67- 67 - 3x = -67
-3x = -67
(divide both sides by -3)
x = 22.33
y = 15 - 22.33
y = -7.33

i think.. im not too sure

Answer 3

xy = 15
x = 4y + 7

substitute in
(4y + 7)y = 15
4y^2 + 7y = 15
4y^2 + 7y - 15 = 0
(4y - 5)(y + 3) = 0
y = 5/4 or y = -3

numbers -3 and -5
number 12 and 1 1/4

Answer 4

p yea this ^ is ryt i didn't see it's product my bad