Question

I am learning quadratic formulas...I need help solving this equation...x(x-3)=x-9

Answer 1

x(x-3)=x-9

x^2 - 3x = x - 9

x^2 - 3x + x + 9 = 0

x ^2 - 2x + 9 = 0

for quadratic equation your equation must be equal to,
ax^2 + bx + c.

so here,

a = 1
b = -2
c = 9.

insert these values in the quadratic equation and solve. :)

Answer 2

do i enter the a b and c in again after i have got the x^2-2x+9=0 or is that just the end of it